The value of \int_0^1 \frac{a - bx^2}{(a + bx^2)^2}\,dx is: — Mathematics 2024

Question 13 Mathematics 2024 Medium MCQ +5.00 marks · -1.00 negative

The value of \(\int_0^1 \frac{a - bx^2}{(a + bx^2)^2}\,dx\) is:

A. \(\frac{a-b}{a+b}\) B. \(\frac{1}{a-b}\) C. \(\frac{a+b}{2}\) D. \(\frac{1}{a+b}\)

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